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<channel>
	<title>christine farion</title>
	<atom:link href="http://christinemorris.com/feed/" rel="self" type="application/rss+xml" />
	<link>http://christinemorris.com</link>
	<description>i like popcorn</description>
	<lastBuildDate>Sun, 19 May 2013 11:33:14 +0000</lastBuildDate>
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		<title>Accessing Analogue In, Arduino</title>
		<link>http://christinemorris.com/2013/03/accessing-analogue-in-arduino/</link>
		<comments>http://christinemorris.com/2013/03/accessing-analogue-in-arduino/#comments</comments>
		<pubDate>Tue, 26 Mar 2013 15:45:52 +0000</pubDate>
		<dc:creator>CMoz</dc:creator>
				<category><![CDATA[Various Code: Arduino, Processing etc]]></category>

		<guid isPermaLink="false">http://christinemorris.com/?p=2936</guid>
		<description><![CDATA[I&#8217;ve been using lilypad for some projects and I needed MORE pins! I was aware of them saying that you can use the Analogue pins for digital output, but I just wasn&#8217;t sure how. and turns out &#8211; it&#8217;s a lot easier than I thought. So writing this post incase someone else is stuck &#8211; [...]]]></description>
			<content:encoded><![CDATA[<!-- Start Shareaholic LikeButtonSetTop --><!-- End Shareaholic LikeButtonSetTop --><p>I&#8217;ve been using lilypad for some projects and I needed MORE pins! I was aware of them saying that you can use the Analogue pins for digital output, but I just wasn&#8217;t sure how. and turns out &#8211; it&#8217;s a lot easier than I thought. So writing this post incase someone else is stuck &#8211; all you need to do to use the pins is name them in the following convention when coding &#8211; so </p>
<p>Pin 14 = Analog in 0<br />Pin 15 = Analog in 1<br />Pin 16 = Analog in 2<br />Pin 17 = Analog in 3<br />Pin 18 = Analog in 4<br />Pin 19 = Analog in 5</p>
<p>These are typically marked A0 A1 A2 and so on. These are not PWM pins is the only thing to be aware of. There is <a href="https://code.google.com/p/rogue-code/wiki/SoftPWMLibraryDocumentation">a PWM library you can download</a>, which does a software version. I haven&#8217;t needed to do this so I&#8217;m not sure how well it works. It&#8217;s described as &#8220;An Arduino and Wiring Library to produce PWM signals on any arbitrary pin.&#8221;</p>
<p>Sample would be </p>
<p>int led = 15; //the LED is on pin A1, which is 15</p>
<p>Easy Peasy.</p>
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		<title>Basic Electronic Formulae</title>
		<link>http://christinemorris.com/2013/01/basic-electronic-formulae/</link>
		<comments>http://christinemorris.com/2013/01/basic-electronic-formulae/#comments</comments>
		<pubDate>Mon, 28 Jan 2013 22:14:51 +0000</pubDate>
		<dc:creator>CMoz</dc:creator>
				<category><![CDATA[Various Code: Arduino, Processing etc]]></category>
		<category><![CDATA[ohms law]]></category>

		<guid isPermaLink="false">http://christinemorris.com/?p=2927</guid>
		<description><![CDATA[I came across this really helpful page over at http://www.bitsbox.co.uk/ where I&#8217;ve bought some of my components from. It&#8217;s handy to have so wanted a copy here where I can find it! There is more information on their page, such as resistors in series etc&#8230;  Original post: Basic Electronic Formulae. Ohms law.  The voltage across a resistance is [...]]]></description>
			<content:encoded><![CDATA[<!-- Start Shareaholic LikeButtonSetTop --><!-- End Shareaholic LikeButtonSetTop --><p>I came across this really helpful page over at http://www.bitsbox.co.uk/ where I&#8217;ve bought some of my components from. It&#8217;s handy to have so wanted a copy here where I can find it! There is more information on their page, such as resistors in series etc&#8230; </p>
<p>Original post: <a href="http://www.bitsbox.co.uk/infocontent/basform.html">Basic Electronic Formulae</a>.</p>
<p><span style="font-family: arial, helvetica, sans-serif; font-size: small;"><span class="mainbody" style="line-height: normal;">Ohms law.</span><span class="mainbody" style="line-height: normal;">  </span></span><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /><span class="mainbody" style="font-family: arial, helvetica, sans-serif; font-size: small; line-height: normal;">The voltage across a resistance is equal to the current passing through the resistance (in Amps) multiplied by the value of the resistance (in Ohms).</span><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /><span style="font-family: arial, helvetica, sans-serif; font-size: small;"><big class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal; font-weight: bold;"><br /></big></span></p>
<div style="font-family: Times; font-size: medium; line-height: normal; text-align: center;"><span style="font-family: arial, helvetica, sans-serif; font-size: small;"><big><span class="mainbody" style="font-weight: bold;">            </span><span style="color: #ff0000;"><span class="mainbody" style="font-weight: bold;">Voltage = Current x Resistance     or     V=IR</span><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; font-weight: bold;" /><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; color: #000000; font-weight: bold;" /><span class="mainbody" style="font-weight: bold;">V=IR    or    I=V/R    or    R=V/I</span><br /></span></big></span></div>
<div> </div>
<div> <span id="more-2927"></span></div>
<div><big><big><span class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal; font-weight: bold;">Power:</span><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /><span class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;">The power (in Watts) dissipated by a resistance is equal to the current (in Amps) passing through the resistance multiplied by the voltage (in Volts) across it.</span><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /></big></big></p>
<div class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal; text-align: center;">            <big><span style="color: #ff0000;">Power = Current x Voltage     or     P=IV</span></big></div>
<p><big><big><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /><span class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;">Using Ohms Law to substitute the voltage term we get:</span><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /></big></big></p>
<div class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal; text-align: center;">            <big><span style="color: #ff0000;">P = I x (IR)     or    P = I²R</span></big></div>
<p><big><big><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /><span class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;">Using Ohms Law to substitute the current term we get:</span><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /></big></big></p>
<div class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal; text-align: center;">            <big><span style="color: #ff0000;">P = (V/R) x V    or    P = V²/R</span></big></div>
<p><big><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /><span class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;">As a practical example of this -</span><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /><span class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;">Q &#8211; Why would a person moving home from the UK to the USA be well advised to buy a new electric kettle?</span><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /><span class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;">A &#8211; The kettle in the UK is rated at 2000 Watts on a voltage of 230V.</span><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /><span class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;">Applying the formula P = V²/R we can find the resistance of the kettle:</span><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /><span class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;">            </span><span class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal; color: #3333ff; font-style: italic;">R = V²/P = 230²/2000 = 26.45 Ohms</span><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /><span class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;">If the kettle were to be plugged into a 120V USA supply, its power would be:</span><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /><span class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;">            </span><span class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal; color: #3333ff; font-style: italic;">P = V²/R = 120²/26.45 = 544.4 Watts</span><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /><span class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;">So, the kettle would produce around a quarter of the heat and would take roughly four times as long to boil.</span><br class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;" /><span class="mainbody" style="font-family: Arial, Helvetica, sans-serif; font-size: 0.7em; line-height: normal;">If you halve the voltage, you get a quarter of the power.</span><br style="font-family: Times; font-size: medium; line-height: normal;" /></big></p>
</div>
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		<item>
		<title>How To Construct Questionnaires &#124; A Practical Guide to Research Methods &#124; Business &#124; How To &#124; Read Free Online Books at How To</title>
		<link>http://christinemorris.com/2013/01/how-to-construct-questionnaires-a-practical-guide-to-research-methods-business-how-to-read-free-online-books-at-how-to/</link>
		<comments>http://christinemorris.com/2013/01/how-to-construct-questionnaires-a-practical-guide-to-research-methods-business-how-to-read-free-online-books-at-how-to/#comments</comments>
		<pubDate>Sat, 26 Jan 2013 00:35:26 +0000</pubDate>
		<dc:creator>CMoz</dc:creator>
				<category><![CDATA[PhD Related]]></category>

		<guid isPermaLink="false">http://christinemorris.com/?p=2925</guid>
		<description><![CDATA[This write up has some good general tips for creating a questionnaire. Good to refer to when you are writing one or to modify one that you&#8217;re working on.  How To Construct Questionnaires &#124; A Practical Guide to Research Methods &#124; Business &#124; How To &#124; Read Free Online Books at How To.]]></description>
			<content:encoded><![CDATA[<!-- Start Shareaholic LikeButtonSetTop --><!-- End Shareaholic LikeButtonSetTop --><p>This write up has some good general tips for creating a questionnaire. Good to refer to when you are writing one or to modify one that you&#8217;re working on. </p>
<p><a href="http://www.howto.co.uk/business/research-methods/how_to_construct_questionnaires/">How To Construct Questionnaires | A Practical Guide to Research Methods | Business | How To | Read Free Online Books at How To</a>.</p>
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		<title>Apple applies for patent on &#8216;smart shoe&#8217; sensor</title>
		<link>http://christinemorris.com/2013/01/apple-applies-for-patent-on-smart-shoe-sensor/</link>
		<comments>http://christinemorris.com/2013/01/apple-applies-for-patent-on-smart-shoe-sensor/#comments</comments>
		<pubDate>Fri, 25 Jan 2013 14:09:55 +0000</pubDate>
		<dc:creator>CMoz</dc:creator>
				<category><![CDATA[PhD Related]]></category>

		<guid isPermaLink="false">http://christinemorris.com/?p=2924</guid>
		<description><![CDATA[This is really interesting and has potential applications in the study I&#8217;m currently doing in Assistive Technology. &#8220;In a patent filed back in July 2012, Curtis Vock and Perry Youngs are listed as the inventors of a &#8220;shoe wear-out sensor, body-bar sensing system, unitless activity assessment and associated methods,&#8221; with Apple Inc. as the assignee. [...]]]></description>
			<content:encoded><![CDATA[<!-- Start Shareaholic LikeButtonSetTop --><!-- End Shareaholic LikeButtonSetTop --><p><span style="color: #444444; font-family: Helvetica, Arial, sans-serif; font-size: 14px; line-height: 21px; background-color: #ffffff;">This is really interesting and has potential applications in the study I&#8217;m currently doing in Assistive Technology. </span></p>
<p><span style="color: #444444; font-family: Helvetica, Arial, sans-serif; font-size: 14px; line-height: 21px; background-color: #ffffff;">&#8220;In a patent filed back in July 2012, Curtis Vock and Perry Youngs are listed as the inventors of a &#8220;shoe wear-out sensor, body-bar sensing system, unitless activity assessment and associated methods,&#8221; with Apple Inc. as the assignee. Vock is an intellectual property lawyer with Lathrop &amp; Gage, a law firm based in Boulder, Colo.&#8221; All the information / full article is available:</span></p>
<p><a href="http://www.tuaw.com/2013/01/24/apple-applies-for-patent-on-smart-shoe-sensor/">Apple applies for patent on &#8216;smart shoe&#8217; sensor | TUAW &#8211; The Unofficial Apple Weblog</a>.</p>
<p><img src="http://www.blogcdn.com//media/2013/01/appleishoe0124-1.jpg" alt="" width="456" height="167" border="0" /></p>
<p>&nbsp;</p>
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		<title>Dynamic Label Creation</title>
		<link>http://christinemorris.com/2013/01/dynamic-label-creation/</link>
		<comments>http://christinemorris.com/2013/01/dynamic-label-creation/#comments</comments>
		<pubDate>Fri, 25 Jan 2013 14:07:23 +0000</pubDate>
		<dc:creator>CMoz</dc:creator>
				<category><![CDATA[iOS Code: snippets, tips, tricks, help]]></category>
		<category><![CDATA[code]]></category>
		<category><![CDATA[dynamic]]></category>
		<category><![CDATA[ios]]></category>
		<category><![CDATA[label]]></category>
		<category><![CDATA[obj c]]></category>
		<category><![CDATA[Xcode]]></category>

		<guid isPermaLink="false">http://christinemorris.com/?p=2923</guid>
		<description><![CDATA[Dynamically creating a label was one of the things I was looking at, dynamically creating any UI object really – and also the placement of it at different random coordinates was important. This is the code I implemented for the iPad app which is landscape orientation. //Create a label int labelX = arc4random() % 904; [...]]]></description>
			<content:encoded><![CDATA[<!-- Start Shareaholic LikeButtonSetTop --><!-- End Shareaholic LikeButtonSetTop --><p>Dynamically creating a label was one of the things I was looking at, dynamically creating any UI object really – and also the placement of it at different random coordinates was important. This is the code I implemented for the iPad app which is landscape orientation.</p>
<p>//Create a label</p>
<p>int labelX = arc4random() % 904;   // the maximum number I would like it to start at – minus the width of the label.</p>
<p>int labelY = arc4random() % 840;  // the maximum height area, minus the label height.</p>
<p>UILabel *randomFactsLabel = [[UILabel alloc] initWithFrame:CGRectMake(labelX, labelY, 100.0, 20.0)];</p>
<p>[randomFactsLabel setTextAlignment:UITextAlignmentCenter]; // other options such as text colour etc</p>
<p>[self.view addSubview:randomFactsLabel]; // to display the label</p>
<p>&nbsp;</p>
<p>If the coordinates are exact, just replace (labelX, labelY… with the x and y coordinates of where you want your label.</p>
<p>&nbsp;</p>
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		<item>
		<title>I&#8217;m Moving: Academic Site&#8230;</title>
		<link>http://christinemorris.com/2013/01/academic-site/</link>
		<comments>http://christinemorris.com/2013/01/academic-site/#comments</comments>
		<pubDate>Sun, 20 Jan 2013 21:00:22 +0000</pubDate>
		<dc:creator>CMoz</dc:creator>
				<category><![CDATA[PhD Related]]></category>

		<guid isPermaLink="false">http://christinemorris.com/?p=2913</guid>
		<description><![CDATA[Just a little post to say that all my academic work has now moved over to Christine Farion. I&#8217;ll be using this site a lot less at the moment so I hope you head over to the new, and updated site! Thanks. (I&#8217;ll still try to answer questions on the Theme Hospital post which seems [...]]]></description>
			<content:encoded><![CDATA[<p style="text-align: left;"><a href="http://christinemorris.com/2013/01/academic-site/img_0692/" rel="attachment wp-att-2914"><img class="wp-image-2914 alignleft" style="border: 1px solid black; margin-left: 10px; margin-right: 10px;" title="IMG_0692" src="http://christinemorris.com/wp-content/uploads/2013/01/IMG_0692-1024x764.jpg" alt="" width="155" height="115" /></a>Just a little post to say that all my academic work has now moved over to <a href="http://christinefarion.com">Christine Farion</a>. I&#8217;ll be using this site a lot less at the moment so I hope you head over to the new, and updated site! Thanks.</p>
<p style="text-align: left;">(I&#8217;ll still try to answer questions on the <a href="http://christinemorris.com/2011/04/theme-hospital-on-your-mac/">Theme Hospital</a> post which seems to have been my most popular!)</p>
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		<title>DeLorean Hovers!</title>
		<link>http://christinemorris.com/2013/01/delorean-hovers/</link>
		<comments>http://christinemorris.com/2013/01/delorean-hovers/#comments</comments>
		<pubDate>Thu, 10 Jan 2013 21:08:52 +0000</pubDate>
		<dc:creator>CMoz</dc:creator>
				<category><![CDATA[Geek Things, fun bits & bytes ~]]></category>

		<guid isPermaLink="false">http://christinemorris.com/?p=2917</guid>
		<description><![CDATA[&#160; It&#8217;s 2013 and the Hoverboard from Back to the Future we&#8217;ve been promised is nowhere to be seen. But at least we can console ourselves with this bit of awesomeness: the DeLorean Hovercraft, as captured by YouTuber Terry Barentsen while filming near the Golden Gate Bridge. (Y&#8217;know, John actually told us about it back [...]]]></description>
			<content:encoded><![CDATA[<!-- Start Shareaholic LikeButtonSetTop --><!-- End Shareaholic LikeButtonSetTop --><p><iframe src="http://www.youtube.com/embed/jh8RX4xDs_k" frameborder="0" width="560" height="315"></iframe></p>
<p>&nbsp;</p>
<p>It&#8217;s 2013 and the Hoverboard from Back to the Future we&#8217;ve been promised is nowhere to be seen. But at least we can console ourselves with this bit of awesomeness: the DeLorean Hovercraft, as captured by YouTuber Terry Barentsen while filming near the Golden Gate Bridge. (Y&#8217;know, John actually told us about it back in August last year &#8211; but it&#8217;s too cool not to refeature it here)</p>
<p>via <a href="http://getpocket.com/a/read/284830540">Pocket : Great Scott! DeLorean Hovercraft in San Francisco</a>.</p>
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		<title>Siri on iPhone 4</title>
		<link>http://christinemorris.com/2013/01/siri-on-iphone-4/</link>
		<comments>http://christinemorris.com/2013/01/siri-on-iphone-4/#comments</comments>
		<pubDate>Wed, 02 Jan 2013 21:13:17 +0000</pubDate>
		<dc:creator>CMoz</dc:creator>
				<category><![CDATA[App related things]]></category>
		<category><![CDATA[Geek Things, fun bits & bytes ~]]></category>

		<guid isPermaLink="false">http://christinemorris.com/?p=2918</guid>
		<description><![CDATA[Great article from http://jailbreakhow.net/how-to-install-siri-on-iphone-4-ipod-touch-4g/ &#8220;How to install siri on iPhone 4? Last few weeks we tried many Cydia tweaks that allow you to port Siri on iPhone 4, like H1Siri and Spire. But the main issue with such tweaks was how to create and install Siri Proxy. But now we will show you how to avoid [...]]]></description>
			<content:encoded><![CDATA[<!-- Start Shareaholic LikeButtonSetTop --><!-- End Shareaholic LikeButtonSetTop --><p>Great article from <a href="http://jailbreakhow.net/how-to-install-siri-on-iphone-4-ipod-touch-4g/">http://jailbreakhow.net/how-to-install-siri-on-iphone-4-ipod-touch-4g/</a></p>
<p>&#8220;How to install siri on iPhone 4? Last few weeks we tried many Cydia tweaks that allow you to port Siri on iPhone 4, like H1Siri and Spire. But the main issue with such tweaks was how to create and install Siri Proxy. But now we will show you how to avoid these complicated steps. Here’s a new Cydia tweak called Siriport that allows you to port Siri on iPhone 4 and iPod touch 4G with few simple steps.&#8221;</p>
<p><iframe src="http://www.youtube.com/embed/KzNa8WVxwn0" frameborder="0" width="560" height="315"></iframe></p>
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		<title>Smart Bike</title>
		<link>http://christinemorris.com/2012/12/smart-bike/</link>
		<comments>http://christinemorris.com/2012/12/smart-bike/#comments</comments>
		<pubDate>Thu, 20 Dec 2012 21:17:05 +0000</pubDate>
		<dc:creator>CMoz</dc:creator>
				<category><![CDATA[Geek Things, fun bits & bytes ~]]></category>
		<category><![CDATA[Media: Video, Photos, YouTube Clips]]></category>

		<guid isPermaLink="false">http://christinemorris.com/?p=2920</guid>
		<description><![CDATA[This is just super cool &#8211; wish I had one!  Move faster, more relaxed, and always modern to your destination: that is the urban mobility 2.0 from smart. The smart electric bike makes city driving enjoyable with its exceptional functionality and exciting innovative features. More information athttp://www.smart.com/ebike]]></description>
			<content:encoded><![CDATA[<!-- Start Shareaholic LikeButtonSetTop --><!-- End Shareaholic LikeButtonSetTop --><p>This is just super cool &#8211; wish I had one! </p>
<p>Move faster, more relaxed, and always modern to your destination: that is the urban mobility 2.0 from smart. The smart electric bike makes city driving enjoyable with its exceptional functionality and exciting innovative features. More information at<a title="http://www.smart.com/ebike" dir="ltr" href="http://www.smart.com/ebike" rel="nofollow" target="_blank">http://www.smart.com/ebike</a></p>
<p><iframe src="http://www.youtube.com/embed/eJMEjAfECR8" frameborder="0" width="560" height="315"></iframe></p>
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		<title>Get Started with Apple</title>
		<link>http://christinemorris.com/2012/02/get-started-with-apple/</link>
		<comments>http://christinemorris.com/2012/02/get-started-with-apple/#comments</comments>
		<pubDate>Mon, 20 Feb 2012 09:27:39 +0000</pubDate>
		<dc:creator>CMoz</dc:creator>
				<category><![CDATA[iOS Code: snippets, tips, tricks, help]]></category>
		<category><![CDATA[apple]]></category>
		<category><![CDATA[development]]></category>
		<category><![CDATA[guide]]></category>
		<category><![CDATA[tutorial]]></category>
		<category><![CDATA[Xcode]]></category>

		<guid isPermaLink="false">http://christinemorris.com/?p=2894</guid>
		<description><![CDATA[Apple have released a new guide for people wanting to try app development. It takes you through the basic steps from an overall introduction through to the end of the development process. If you&#8217;ve been curious about trying to make one, and with Xcode being free it seems a great time to try it if [...]]]></description>
			<content:encoded><![CDATA[<!-- Start Shareaholic LikeButtonSetTop --><!-- End Shareaholic LikeButtonSetTop --><p style="text-align: center;"><a href="http://christinemorris.com/2012/02/get-started-with-apple/screen-shot-2012-02-18-at-22-22-31/" rel="attachment wp-att-2895"><img class="aligncenter size-full wp-image-2895" title="Apple Documentation" src="http://christinemorris.com/wp-content/uploads/2012/02/Screen-Shot-2012-02-18-at-22.22.31.png" alt="" width="498" height="351" /></a></p>
<p style="text-align: left;">Apple have released a new guide for people wanting to try app development. It takes you through the basic steps from an overall introduction through to the end of the development process. If you&#8217;ve been curious about trying to make one, and with Xcode being free it seems a great time to try it if you&#8217;ve always put it off. Obviously this is a pretty basic intro and you might not be creating the next angry birds, but it is a really great way to see if you think app development might be for you, and get it up and running. </p>
<p style="text-align: left;">The guide can be found here on the <a href="https://developer.apple.com/library/ios/#referencelibrary/GettingStarted/RoadMapiOS/Introduction/Introduction.html">Developer site</a>. </p>
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